1100021122313 has 4 divisors (see below), whose sum is σ = 1100365851648. Its totient is φ = 1099676392980.

The previous prime is 1100021122301. The next prime is 1100021122327. The reversal of 1100021122313 is 3132211200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100021122313 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1100021122291 and 1100021122300.

It is not an unprimeable number, because it can be changed into a prime (1100021122373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172359881 + ... + 172366262.

It is an arithmetic number, because the mean of its divisors is an integer number (275091462912).

Almost surely, 2^{1100021122313} is an apocalyptic number.

It is an amenable number.

1100021122313 is a deficient number, since it is larger than the sum of its proper divisors (344729335).

1100021122313 is an equidigital number, since it uses as much as digits as its factorization.

1100021122313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344729334.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1100021122313 its reverse (3132211200011), we get a palindrome (4232232322324).

The spelling of 1100021122313 in words is "one trillion, one hundred billion, twenty-one million, one hundred twenty-two thousand, three hundred thirteen".