Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11110011101110111 |
3 | 1001101121211122010001 |
4 | 22033222132131313 |
5 | 140012023230234 |
6 | 5015312412131 |
7 | 536411152636 |
oct | 121752363567 |
9 | 31347748101 |
10 | 11000211319 |
11 | 4735372639 |
12 | 216bb47047 |
13 | 1063c9c8a6 |
14 | 764d2751d |
15 | 445ad1d14 |
hex | 28fa9e777 |
11000211319 has 2 divisors, whose sum is σ = 11000211320. Its totient is φ = 11000211318.
The previous prime is 11000211197. The next prime is 11000211323. The reversal of 11000211319 is 91311200011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000211319 - 211 = 11000209271 is a prime.
It is a super-2 number, since 2×110002113192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11000211296 and 11000211305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000211359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105659 + 5500105660.
It is an arithmetic number, because the mean of its divisors is an integer number (5500105660).
Almost surely, 211000211319 is an apocalyptic number.
11000211319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000211319 is an equidigital number, since it uses as much as digits as its factorization.
11000211319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
The spelling of 11000211319 in words is "eleven billion, two hundred eleven thousand, three hundred nineteen".
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