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11000211319 is a prime number
BaseRepresentation
bin10100011111010100…
…11110011101110111
31001101121211122010001
422033222132131313
5140012023230234
65015312412131
7536411152636
oct121752363567
931347748101
1011000211319
114735372639
12216bb47047
131063c9c8a6
14764d2751d
15445ad1d14
hex28fa9e777

11000211319 has 2 divisors, whose sum is σ = 11000211320. Its totient is φ = 11000211318.

The previous prime is 11000211197. The next prime is 11000211323. The reversal of 11000211319 is 91311200011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000211319 - 211 = 11000209271 is a prime.

It is a super-2 number, since 2×110002113192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000211296 and 11000211305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000211359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105659 + 5500105660.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105660).

Almost surely, 211000211319 is an apocalyptic number.

11000211319 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211319 is an equidigital number, since it uses as much as digits as its factorization.

11000211319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 11000211319 in words is "eleven billion, two hundred eleven thousand, three hundred nineteen".