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1100021219981 is a prime number
BaseRepresentation
bin10000000000011110010…
…111111100001010001101
310220011100100222212001222
4100000132113330022031
5121010320413014411
62201202012213125
7142321360044245
oct20003627741215
93804310885058
101100021219981
11394575334972
12159236a6a1a5
137c9682c7a88
143b35422cb25
151d9327934db
hex1001e5fc28d

1100021219981 has 2 divisors, whose sum is σ = 1100021219982. Its totient is φ = 1100021219980.

The previous prime is 1100021219953. The next prime is 1100021220007. The reversal of 1100021219981 is 1899121200011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1043736029956 + 56285190025 = 1021634^2 + 237245^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100021219981 - 222 = 1100017025677 is a prime.

It is a super-2 number, since 2×11000212199812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100021219951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010609990 + 550010609991.

It is an arithmetic number, because the mean of its divisors is an integer number (550010609991).

Almost surely, 21100021219981 is an apocalyptic number.

It is an amenable number.

1100021219981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100021219981 is an equidigital number, since it uses as much as digits as its factorization.

1100021219981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 35.

Adding to 1100021219981 its reverse (1899121200011), we get a palindrome (2999142419992).

The spelling of 1100021219981 in words is "one trillion, one hundred billion, twenty-one million, two hundred nineteen thousand, nine hundred eighty-one".