11000214011 has 2 divisors, whose sum is σ = 11000214012. Its totient is φ = 11000214010.

The previous prime is 11000213957. The next prime is 11000214019. The reversal of 11000214011 is 11041200011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000214011 - 2¹⁰ = 11000212987 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000213983 and 11000214001.

It is not a weakly prime, because it can be changed into another prime (11000214019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500107005 + 5500107006.

It is an arithmetic number, because the mean of its divisors is an integer number (5500107006).

Almost surely, 2^11000214011 is an apocalyptic number.

11000214011 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000214011 is an equidigital number, since it uses as much as digits as its factorization.

11000214011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 11000214011 its reverse (11041200011), we get a palindrome (22041414022).

The spelling of 11000214011 in words is "eleven billion, two hundred fourteen thousand, eleven".