Base | Representation |
---|---|
bin | 1010000000010011000000… |
… | …1101100101010001101111 |
3 | 1102221121111020211112012002 |
4 | 2200010300031211101233 |
5 | 2420211422322040413 |
6 | 35221233101202515 |
7 | 2213511465124244 |
oct | 240046015452157 |
9 | 42847436745162 |
10 | 11000220111983 |
11 | 3561192529343 |
12 | 1297abb56043b |
13 | 61a415c0072b |
14 | 2a05b08b15cb |
15 | 14121ab87958 |
hex | a013036546f |
11000220111983 has 4 divisors (see below), whose sum is σ = 11084191258008. Its totient is φ = 10916248965960.
The previous prime is 11000220111917. The next prime is 11000220112009. The reversal of 11000220111983 is 38911102200011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11000220111983 - 212 = 11000220107887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11000220116983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41985572816 + ... + 41985573077.
It is an arithmetic number, because the mean of its divisors is an integer number (2771047814502).
Almost surely, 211000220111983 is an apocalyptic number.
11000220111983 is a deficient number, since it is larger than the sum of its proper divisors (83971146025).
11000220111983 is an equidigital number, since it uses as much as digits as its factorization.
11000220111983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83971146024.
The product of its (nonzero) digits is 864, while the sum is 29.
Adding to 11000220111983 its reverse (38911102200011), we get a palindrome (49911322311994).
The spelling of 11000220111983 in words is "eleven trillion, two hundred twenty million, one hundred eleven thousand, nine hundred eighty-three".
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