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11000220112001 = 17959161251511
BaseRepresentation
bin1010000000010011000000…
…1101100101010010000001
31102221121111020211112012202
42200010300031211102001
52420211422322041001
635221233101202545
72213511465124301
oct240046015452201
942847436745182
1011000220112001
11356119252935a
121297abb560455
1361a415c00743
142a05b08b1601
1514121ab8796b
hexa0130365481

11000220112001 has 4 divisors (see below), whose sum is σ = 11000281543104. Its totient is φ = 11000158680900.

The previous prime is 11000220111917. The next prime is 11000220112009. The reversal of 11000220112001 is 10021102200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000220112001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11000220112009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30446165 + ... + 30805346.

It is an arithmetic number, because the mean of its divisors is an integer number (2750070385776).

Almost surely, 211000220112001 is an apocalyptic number.

It is an amenable number.

11000220112001 is a deficient number, since it is larger than the sum of its proper divisors (61431103).

11000220112001 is an equidigital number, since it uses as much as digits as its factorization.

11000220112001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61431102.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 11000220112001 its reverse (10021102200011), we get a palindrome (21021322312012).

The spelling of 11000220112001 in words is "eleven trillion, two hundred twenty million, one hundred twelve thousand, one".

Divisors: 1 179591 61251511 11000220112001