Base | Representation |
---|---|
bin | 11001000000101111100011… |
… | …010011101111001111011011 |
3 | 112102111002221220210021221122 |
4 | 121000233203103233033123 |
5 | 103404234022040120443 |
6 | 1025542153411555455 |
7 | 32112253404054065 |
oct | 3100574323571733 |
9 | 472432856707848 |
10 | 110002221020123 |
11 | 32060753017513 |
12 | 104072012bbb8b |
13 | 494c21b482653 |
14 | 1d241c8cd0735 |
15 | cab6246d2968 |
hex | 640be34ef3db |
110002221020123 has 2 divisors, whose sum is σ = 110002221020124. Its totient is φ = 110002221020122.
The previous prime is 110002221020119. The next prime is 110002221020141. The reversal of 110002221020123 is 321020122200011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110002221020123 - 22 = 110002221020119 is a prime.
It is not a weakly prime, because it can be changed into another prime (110002221020113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001110510061 + 55001110510062.
It is an arithmetic number, because the mean of its divisors is an integer number (55001110510062).
Almost surely, 2110002221020123 is an apocalyptic number.
110002221020123 is a deficient number, since it is larger than the sum of its proper divisors (1).
110002221020123 is an equidigital number, since it uses as much as digits as its factorization.
110002221020123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 110002221020123 its reverse (321020122200011), we get a palindrome (431022343220134).
The spelling of 110002221020123 in words is "one hundred ten trillion, two billion, two hundred twenty-one million, twenty thousand, one hundred twenty-three".
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