110002221020141 has 2 divisors, whose sum is σ = 110002221020142. Its totient is φ = 110002221020140.

The previous prime is 110002221020123. The next prime is 110002221020179. The reversal of 110002221020141 is 141020122200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95425448274025 + 14576772746116 = 9768595^2 + 3817954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110002221020141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110002221025141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001110510070 + 55001110510071.

It is an arithmetic number, because the mean of its divisors is an integer number (55001110510071).

Almost surely, 2^{110002221020141} is an apocalyptic number.

It is an amenable number.

110002221020141 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002221020141 is an equidigital number, since it uses as much as digits as its factorization.

110002221020141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 110002221020141 its reverse (141020122200011), we get a palindrome (251022343220152).

The spelling of 110002221020141 in words is "one hundred ten trillion, two billion, two hundred twenty-one million, twenty thousand, one hundred forty-one".