1100023313117 has 2 divisors, whose sum is σ = 1100023313118. Its totient is φ = 1100023313116.

The previous prime is 1100023313089. The next prime is 1100023313143. The reversal of 1100023313117 is 7113133200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 904465669156 + 195557643961 = 951034^2 + 442219^2 .

It is an emirp because it is prime and its reverse (7113133200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100023313117 - 2²⁶ = 1099956204253 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100023313092 and 1100023313101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100023313717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011656558 + 550011656559.

It is an arithmetic number, because the mean of its divisors is an integer number (550011656559).

Almost surely, 2^{1100023313117} is an apocalyptic number.

It is an amenable number.

1100023313117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100023313117 is an equidigital number, since it uses as much as digits as its factorization.

1100023313117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 1100023313117 its reverse (7113133200011), we get a palindrome (8213156513128).

The spelling of 1100023313117 in words is "one trillion, one hundred billion, twenty-three million, three hundred thirteen thousand, one hundred seventeen".