110003104220113 has 8 divisors (see below), whose sum is σ = 118936853110656. Its totient is φ = 101136779850000.

The previous prime is 110003104220069. The next prime is 110003104220201. The reversal of 110003104220113 is 311022401300011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 110003104220113 - 2¹³ = 110003104211921 is a prime.

It is a super-3 number, since 3×110003104220113³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110003104223113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16856126713 + ... + 16856133238.

It is an arithmetic number, because the mean of its divisors is an integer number (14867106638832).

Almost surely, 2^{110003104220113} is an apocalyptic number.

110003104220113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

110003104220113 is a deficient number, since it is larger than the sum of its proper divisors (8933748890543).

110003104220113 is a wasteful number, since it uses less digits than its factorization.

110003104220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33712260215.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 110003104220113 its reverse (311022401300011), we get a palindrome (421025505520124).

The spelling of 110003104220113 in words is "one hundred ten trillion, three billion, one hundred four million, two hundred twenty thousand, one hundred thirteen".