Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10111000011010111 |
3 | 1001101122000202020211 |
4 | 22033222313003113 |
5 | 140012034441043 |
6 | 5015314510251 |
7 | 536412052351 |
oct | 121752670327 |
9 | 31348022224 |
10 | 11000312023 |
11 | 4735431268 |
12 | 216bb95387 |
13 | 106400668c |
14 | 764d520d1 |
15 | 445b01a9d |
hex | 28fab70d7 |
11000312023 has 2 divisors, whose sum is σ = 11000312024. Its totient is φ = 11000312022.
The previous prime is 11000311999. The next prime is 11000312039. The reversal of 11000312023 is 32021300011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000312023 - 225 = 10966757591 is a prime.
It is a super-3 number, since 3×110003120233 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11000311994 and 11000312012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000312093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500156011 + 5500156012.
It is an arithmetic number, because the mean of its divisors is an integer number (5500156012).
Almost surely, 211000312023 is an apocalyptic number.
11000312023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000312023 is an equidigital number, since it uses as much as digits as its factorization.
11000312023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11000312023 its reverse (32021300011), we get a palindrome (43021612034).
The spelling of 11000312023 in words is "eleven billion, three hundred twelve thousand, twenty-three".
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