Base | Representation |
---|---|
bin | 11001000000110000011000… |
… | …111101011000101101001111 |
3 | 112102111012021122111122000022 |
4 | 121000300120331120231033 |
5 | 103404242343002132234 |
6 | 1025542423004252355 |
7 | 32112314613632054 |
oct | 3100603075305517 |
9 | 472435248448008 |
10 | 110003121130319 |
11 | 3206107511463a |
12 | 104074128410bb |
13 | 494c332ab7231 |
14 | 1d2427267902b |
15 | cab678731e2e |
hex | 640c18f58b4f |
110003121130319 has 2 divisors, whose sum is σ = 110003121130320. Its totient is φ = 110003121130318.
The previous prime is 110003121130283. The next prime is 110003121130363. The reversal of 110003121130319 is 913031121300011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110003121130319 is a prime.
It is a super-3 number, since 3×1100031211303193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110003121130619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001560565159 + 55001560565160.
It is an arithmetic number, because the mean of its divisors is an integer number (55001560565160).
Almost surely, 2110003121130319 is an apocalyptic number.
110003121130319 is a deficient number, since it is larger than the sum of its proper divisors (1).
110003121130319 is an equidigital number, since it uses as much as digits as its factorization.
110003121130319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 26.
The spelling of 110003121130319 in words is "one hundred ten trillion, three billion, one hundred twenty-one million, one hundred thirty thousand, three hundred nineteen".
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