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110003121130363 is a prime number
BaseRepresentation
bin11001000000110000011000…
…111101011000101101111011
3112102111012021122111122001221
4121000300120331120231323
5103404242343002132423
61025542423004252511
732112314613632146
oct3100603075305573
9472435248448057
10110003121130363
113206107511467a
1210407412841137
13494c332ab7266
141d2427267905d
15cab678731e5d
hex640c18f58b7b

110003121130363 has 2 divisors, whose sum is σ = 110003121130364. Its totient is φ = 110003121130362.

The previous prime is 110003121130319. The next prime is 110003121130403. The reversal of 110003121130363 is 363031121300011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110003121130363 - 221 = 110003119033211 is a prime.

It is a super-3 number, since 3×1100031211303633 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (110003121131363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001560565181 + 55001560565182.

It is an arithmetic number, because the mean of its divisors is an integer number (55001560565182).

Almost surely, 2110003121130363 is an apocalyptic number.

110003121130363 is a deficient number, since it is larger than the sum of its proper divisors (1).

110003121130363 is an equidigital number, since it uses as much as digits as its factorization.

110003121130363 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 110003121130363 its reverse (363031121300011), we get a palindrome (473034242430374).

The spelling of 110003121130363 in words is "one hundred ten trillion, three billion, one hundred twenty-one million, one hundred thirty thousand, three hundred sixty-three".