110003214001413 has 16 divisors (see below), whose sum is σ = 147141518232960. Its totient is φ = 73100564291136.

The previous prime is 110003214001391. The next prime is 110003214001501. The reversal of 110003214001413 is 314100412300011.

It is a de Polignac number, because none of the positive numbers 2^k-110003214001413 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 110003214001413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110003214001313) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45240345 + ... + 47609822.

It is an arithmetic number, because the mean of its divisors is an integer number (9196344889560).

Almost surely, 2^{110003214001413} is an apocalyptic number.

It is an amenable number.

110003214001413 is a deficient number, since it is larger than the sum of its proper divisors (37138304231547).

110003214001413 is an equidigital number, since it uses as much as digits as its factorization.

110003214001413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92851436.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 110003214001413 its reverse (314100412300011), we get a palindrome (424103626301424).

The spelling of 110003214001413 in words is "one hundred ten trillion, three billion, two hundred fourteen million, one thousand, four hundred thirteen".