Base | Representation |
---|---|
bin | 10000000000011111000… |
… | …101010000100110110011 |
3 | 10220011101012100102200111 |
4 | 100000133011100212303 |
5 | 121010331433201321 |
6 | 2201203115002151 |
7 | 142321563034423 |
oct | 20003705204663 |
9 | 3804335312614 |
10 | 1100033100211 |
11 | 394581009741 |
12 | 15923aa39357 |
13 | 7c96a8c73b6 |
14 | 3b355a42483 |
15 | 1d93383d5e1 |
hex | 1001f1509b3 |
1100033100211 has 2 divisors, whose sum is σ = 1100033100212. Its totient is φ = 1100033100210.
The previous prime is 1100033100209. The next prime is 1100033100239. The reversal of 1100033100211 is 1120013300011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100033100211 - 21 = 1100033100209 is a prime.
Together with 1100033100209, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1100033100191 and 1100033100200.
It is not a weakly prime, because it can be changed into another prime (1100033100241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550016550105 + 550016550106.
It is an arithmetic number, because the mean of its divisors is an integer number (550016550106).
Almost surely, 21100033100211 is an apocalyptic number.
1100033100211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100033100211 is an equidigital number, since it uses as much as digits as its factorization.
1100033100211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1100033100211 its reverse (1120013300011), we get a palindrome (2220046400222).
The spelling of 1100033100211 in words is "one trillion, one hundred billion, thirty-three million, one hundred thousand, two hundred eleven".
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