Search a number
-
+
11000331143 = 19578964797
BaseRepresentation
bin10100011111010101…
…11011101110000111
31001101122001201110222
422033222323232013
5140012041044033
65015315134555
7536412162164
oct121752735607
931348051428
1011000331143
11473544466a
12216bba445b
1310640122a9
14764d5906b
15445b07598
hex28fabbb87

11000331143 has 4 divisors (see below), whose sum is σ = 11579295960. Its totient is φ = 10421366328.

The previous prime is 11000331137. The next prime is 11000331161. The reversal of 11000331143 is 34113300011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000331143 - 216 = 11000265607 is a prime.

It is a super-3 number, since 3×110003311433 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000331113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289482380 + ... + 289482417.

It is an arithmetic number, because the mean of its divisors is an integer number (2894823990).

Almost surely, 211000331143 is an apocalyptic number.

11000331143 is a deficient number, since it is larger than the sum of its proper divisors (578964817).

11000331143 is an equidigital number, since it uses as much as digits as its factorization.

11000331143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 578964816.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11000331143 its reverse (34113300011), we get a palindrome (45113631154).

The spelling of 11000331143 in words is "eleven billion, three hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 19 578964797 11000331143