11000331331201 has 4 divisors (see below), whose sum is σ = 11001849253632. Its totient is φ = 10998813408772.

The previous prime is 11000331331169. The next prime is 11000331331229. The reversal of 11000331331201 is 10213313300011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000331331201 - 2⁵ = 11000331331169 is a prime.

It is a super-2 number, since 2×11000331331201² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000331331501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 758950345 + ... + 758964838.

It is an arithmetic number, because the mean of its divisors is an integer number (2750462313408).

Almost surely, 2^{11000331331201} is an apocalyptic number.

It is an amenable number.

11000331331201 is a deficient number, since it is larger than the sum of its proper divisors (1517922431).

11000331331201 is an equidigital number, since it uses as much as digits as its factorization.

11000331331201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1517922430.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11000331331201 its reverse (10213313300011), we get a palindrome (21213644631212).

The spelling of 11000331331201 in words is "eleven trillion, three hundred thirty-one million, three hundred thirty-one thousand, two hundred one".