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11000331331501 is a prime number
BaseRepresentation
bin1010000000010011011011…
…0101110110011110101101
31102221121210000010001200111
42200010312311312132231
52420212134310102001
635221252113100021
72213514315355351
oct240046665663655
942847700101614
1011000331331501
11356123a2931a6
121297b30857611
1361a432c71bb5
142a05c1583461
15141225806851
hexa0136d767ad

11000331331501 has 2 divisors, whose sum is σ = 11000331331502. Its totient is φ = 11000331331500.

The previous prime is 11000331331481. The next prime is 11000331331579. The reversal of 11000331331501 is 10513313300011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10969681826601 + 30649504900 = 3312051^2 + 175070^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000331331501 - 225 = 11000297777069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000331431501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500165665750 + 5500165665751.

It is an arithmetic number, because the mean of its divisors is an integer number (5500165665751).

Almost surely, 211000331331501 is an apocalyptic number.

It is an amenable number.

11000331331501 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000331331501 is an equidigital number, since it uses as much as digits as its factorization.

11000331331501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 22.

Adding to 11000331331501 its reverse (10513313300011), we get a palindrome (21513644631512).

The spelling of 11000331331501 in words is "eleven trillion, three hundred thirty-one million, three hundred thirty-one thousand, five hundred one".