Base | Representation |
---|---|
bin | 1010000000010011110101… |
… | …1100000110010111011101 |
3 | 1102221122001201101200121012 |
4 | 2200010331130012113131 |
5 | 2420212401124140331 |
6 | 35221311105345005 |
7 | 2213520131252303 |
oct | 240047534062735 |
9 | 42848051350535 |
10 | 11000442021341 |
11 | 3561296816103 |
12 | 1297b61938165 |
13 | 61a44cb89246 |
14 | 2a05d2158273 |
15 | 1412303bd82b |
hex | a013d7065dd |
11000442021341 has 2 divisors, whose sum is σ = 11000442021342. Its totient is φ = 11000442021340.
The previous prime is 11000442021329. The next prime is 11000442021419. The reversal of 11000442021341 is 14312024400011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7757366892025 + 3243075129316 = 2785205^2 + 1800854^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000442021341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000442021941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500221010670 + 5500221010671.
It is an arithmetic number, because the mean of its divisors is an integer number (5500221010671).
Almost surely, 211000442021341 is an apocalyptic number.
It is an amenable number.
11000442021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000442021341 is an equidigital number, since it uses as much as digits as its factorization.
11000442021341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11000442021341 its reverse (14312024400011), we get a palindrome (25312466421352).
The spelling of 11000442021341 in words is "eleven trillion, four hundred forty-two million, twenty-one thousand, three hundred forty-one".
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