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11000819939 is a prime number
BaseRepresentation
bin10100011111011001…
…10011000011100011
31001101122222112222112
422033230303003203
5140012202214224
65015333425535
7536416266224
oct121754630343
931348875875
1011000819939
11473574892a
12217019b2ab
131064153915
1476504524b
15445ba230e
hex28fb330e3

11000819939 has 2 divisors, whose sum is σ = 11000819940. Its totient is φ = 11000819938.

The previous prime is 11000819927. The next prime is 11000819941. The reversal of 11000819939 is 93991800011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000819939 is a prime.

It is a Sophie Germain prime.

Together with 11000819941, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000819896 and 11000819905.

It is not a weakly prime, because it can be changed into another prime (11000839939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500409969 + 5500409970.

It is an arithmetic number, because the mean of its divisors is an integer number (5500409970).

Almost surely, 211000819939 is an apocalyptic number.

11000819939 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000819939 is an equidigital number, since it uses as much as digits as its factorization.

11000819939 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 41.

The spelling of 11000819939 in words is "eleven billion, eight hundred nineteen thousand, nine hundred thirty-nine".