Base | Representation |
---|---|
bin | 1010000000010101010011… |
… | …0100000001000010010111 |
3 | 1102221200002001021202020002 |
4 | 2200011110310001002113 |
5 | 2420214202021320220 |
6 | 35221414034401515 |
7 | 2213532632402024 |
oct | 240052464010227 |
9 | 42850061252202 |
10 | 11000834166935 |
11 | 3561478106978 |
12 | 129805113029b |
13 | 61a4b31aa762 |
14 | 2a062c27654b |
15 | 141254a2ec75 |
hex | a0154d01097 |
11000834166935 has 4 divisors (see below), whose sum is σ = 13201001000328. Its totient is φ = 8800667333544.
The previous prime is 11000834166929. The next prime is 11000834166961. The reversal of 11000834166935 is 53966143800011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11000834166935 - 210 = 11000834165911 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11000834166935.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100083416689 + ... + 1100083416698.
It is an arithmetic number, because the mean of its divisors is an integer number (3300250250082).
Almost surely, 211000834166935 is an apocalyptic number.
11000834166935 is a deficient number, since it is larger than the sum of its proper divisors (2200166833393).
11000834166935 is an equidigital number, since it uses as much as digits as its factorization.
11000834166935 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2200166833392.
The product of its (nonzero) digits is 466560, while the sum is 47.
Adding to 11000834166935 its reverse (53966143800011), we get a palindrome (64966977966946).
The spelling of 11000834166935 in words is "eleven trillion, eight hundred thirty-four million, one hundred sixty-six thousand, nine hundred thirty-five".
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