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11000976792473 is a prime number
BaseRepresentation
bin1010000000010101110101…
…0100000101101110011001
31102221200102222122212200102
42200011131110011232121
52420220000024324343
635221440131345145
72213536313605643
oct240053524055631
942850388585612
1011000976792473
113561540671618
121298090a521b5
1361a5068c6b75
142a06431a1893
151412623043b8
hexa015d505b99

11000976792473 has 2 divisors, whose sum is σ = 11000976792474. Its totient is φ = 11000976792472.

The previous prime is 11000976792467. The next prime is 11000976792479. The reversal of 11000976792473 is 37429767900011.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (11000976792467) and next prime (11000976792479).

It can be written as a sum of positive squares in only one way, i.e., 5928626005129 + 5072350787344 = 2434877^2 + 2252188^2 .

It is an emirp because it is prime and its reverse (37429767900011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000976792473 - 28 = 11000976792217 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000976792479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500488396236 + 5500488396237.

It is an arithmetic number, because the mean of its divisors is an integer number (5500488396237).

Almost surely, 211000976792473 is an apocalyptic number.

It is an amenable number.

11000976792473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000976792473 is an equidigital number, since it uses as much as digits as its factorization.

11000976792473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4000752, while the sum is 56.

The spelling of 11000976792473 in words is "eleven trillion, nine hundred seventy-six million, seven hundred ninety-two thousand, four hundred seventy-three".