Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …100100110000101001011101 |
3 | 112102111212001202100002022112 |
4 | 121000312303210300221131 |
5 | 103404401000042014212 |
6 | 1025545522335123405 |
7 | 32112650414201414 |
oct | 3100666344605135 |
9 | 472455052302275 |
10 | 110010010110557 |
11 | 32063a8a830437 |
12 | 10408815973565 |
13 | 494cb900bb8bb |
14 | 1d2472757647b |
15 | cab92d41b422 |
hex | 640db3930a5d |
110010010110557 has 2 divisors, whose sum is σ = 110010010110558. Its totient is φ = 110010010110556.
The previous prime is 110010010110551. The next prime is 110010010110589. The reversal of 110010010110557 is 755011010010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72832467229636 + 37177542880921 = 8534194^2 + 6097339^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010010110557 - 228 = 110009741675101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010010110551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005055278 + 55005005055279.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005055279).
Almost surely, 2110010010110557 is an apocalyptic number.
It is an amenable number.
110010010110557 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010010110557 is an equidigital number, since it uses as much as digits as its factorization.
110010010110557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 175, while the sum is 23.
Adding to 110010010110557 its reverse (755011010010011), we get a palindrome (865021020120568).
The spelling of 110010010110557 in words is "one hundred ten trillion, ten billion, ten million, one hundred ten thousand, five hundred fifty-seven".
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