Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …101000100010001111100101 |
3 | 112102111212001211012100202111 |
4 | 121000312303220202033211 |
5 | 103404401000320201013 |
6 | 1025545522412241021 |
7 | 32112650425462444 |
oct | 3100666350421745 |
9 | 472455054170674 |
10 | 110010011100133 |
11 | 32063a90346971 |
12 | 10408816170171 |
13 | 494cb90377151 |
14 | 1d24727752d5b |
15 | cab92d56473d |
hex | 640db3a223e5 |
110010011100133 has 2 divisors, whose sum is σ = 110010011100134. Its totient is φ = 110010011100132.
The previous prime is 110010011100103. The next prime is 110010011100173. The reversal of 110010011100133 is 331001110010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96537345416964 + 13472665683169 = 9825342^2 + 3670513^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010011100133 - 233 = 110001421165541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010011100103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005550066 + 55005005550067.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005550067).
Almost surely, 2110010011100133 is an apocalyptic number.
It is an amenable number.
110010011100133 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010011100133 is an equidigital number, since it uses as much as digits as its factorization.
110010011100133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 13.
Adding to 110010011100133 its reverse (331001110010011), we get a palindrome (441011121110144).
The spelling of 110010011100133 in words is "one hundred ten trillion, ten billion, eleven million, one hundred thousand, one hundred thirty-three".
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