1100100111119 has 2 divisors, whose sum is σ = 1100100111120. Its totient is φ = 1100100111118.

The previous prime is 1100100111101. The next prime is 1100100111211. The reversal of 1100100111119 is 9111110010011.

It is a weak prime.

It is an emirp because it is prime and its reverse (9111110010011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100100111119 is a prime.

It is a super-2 number, since 2×1100100111119² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100100111097 and 1100100111106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100100111619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050055559 + 550050055560.

It is an arithmetic number, because the mean of its divisors is an integer number (550050055560).

Almost surely, 2^{1100100111119} is an apocalyptic number.

1100100111119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100100111119 is an equidigital number, since it uses as much as digits as its factorization.

1100100111119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 17.

The spelling of 1100100111119 in words is "one trillion, one hundred billion, one hundred million, one hundred eleven thousand, one hundred nineteen".