110010011117 has 2 divisors, whose sum is σ = 110010011118. Its totient is φ = 110010011116.

The previous prime is 110010011101. The next prime is 110010011119. The reversal of 110010011117 is 711110010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57929750596 + 52080260521 = 240686^2 + 228211^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010011117 - 2⁴ = 110010011101 is a prime.

Together with 110010011119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010011119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005558 + 55005005559.

It is an arithmetic number, because the mean of its divisors is an integer number (55005005559).

Almost surely, 2^110010011117 is an apocalyptic number.

It is an amenable number.

110010011117 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010011117 is an equidigital number, since it uses as much as digits as its factorization.

110010011117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7, while the sum is 14.

Adding to 110010011117 its reverse (711110010011), we get a palindrome (821120021128).

The spelling of 110010011117 in words is "one hundred ten billion, ten million, eleven thousand, one hundred seventeen".