1100100999947 has 2 divisors, whose sum is σ = 1100100999948. Its totient is φ = 1100100999946.

The previous prime is 1100100999917. The next prime is 1100100999953. The reversal of 1100100999947 is 7499990010011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100100999947 - 2⁸ = 1100100999691 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100100999895 and 1100100999904.

It is not a weakly prime, because it can be changed into another prime (1100100999917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050499973 + 550050499974.

It is an arithmetic number, because the mean of its divisors is an integer number (550050499974).

Almost surely, 2^{1100100999947} is an apocalyptic number.

1100100999947 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100100999947 is an equidigital number, since it uses as much as digits as its factorization.

1100100999947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 183708, while the sum is 50.

The spelling of 1100100999947 in words is "one trillion, one hundred billion, one hundred million, nine hundred ninety-nine thousand, nine hundred forty-seven".