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11001011011097 is a prime number
BaseRepresentation
bin1010000000010101111101…
…0110100111111000011001
31102221200112101001100210212
42200011133112213320121
52420220032304323342
635221443353020505
72213540210504462
oct240053726477031
942850471040725
1011001011011097
113561558a13578
1212980a03b4735
1361a510a18083
142a064794bd69
15141265313182
hexa015f5a7e19

11001011011097 has 2 divisors, whose sum is σ = 11001011011098. Its totient is φ = 11001011011096.

The previous prime is 11001011011063. The next prime is 11001011011117. The reversal of 11001011011097 is 79011011010011.

11001011011097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8680677797401 + 2320333213696 = 2946299^2 + 1523264^2 .

It is an emirp because it is prime and its reverse (79011011010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001011011097 - 212 = 11001011007001 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001011016097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500505505548 + 5500505505549.

It is an arithmetic number, because the mean of its divisors is an integer number (5500505505549).

Almost surely, 211001011011097 is an apocalyptic number.

It is an amenable number.

11001011011097 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001011011097 is an equidigital number, since it uses as much as digits as its factorization.

11001011011097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 23.

The spelling of 11001011011097 in words is "eleven trillion, one billion, eleven million, eleven thousand, ninety-seven".