Base | Representation |
---|---|
bin | 110011001110100011… |
… | …1010011110000000111 |
3 | 101111221210110012002012 |
4 | 1212131013103300013 |
5 | 3300300042334343 |
6 | 122312110404435 |
7 | 10643103413252 |
oct | 1463507236007 |
9 | 344853405065 |
10 | 110010121223 |
11 | 42722933362 |
12 | 193a220071b |
13 | a4b26319b2 |
14 | 547869a099 |
15 | 2cdce46718 |
hex | 199d1d3c07 |
110010121223 has 2 divisors, whose sum is σ = 110010121224. Its totient is φ = 110010121222.
The previous prime is 110010121159. The next prime is 110010121237. The reversal of 110010121223 is 322121010011.
It is an a-pointer prime, because the next prime (110010121237) can be obtained adding 110010121223 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110010121223 - 26 = 110010121159 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110010121198 and 110010121207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010121283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005060611 + 55005060612.
It is an arithmetic number, because the mean of its divisors is an integer number (55005060612).
Almost surely, 2110010121223 is an apocalyptic number.
110010121223 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010121223 is an equidigital number, since it uses as much as digits as its factorization.
110010121223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 110010121223 its reverse (322121010011), we get a palindrome (432131131234).
The spelling of 110010121223 in words is "one hundred ten billion, ten million, one hundred twenty-one thousand, two hundred twenty-three".
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