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11001020213 = 68316106911
BaseRepresentation
bin10100011111011011…
…00011111100110101
31001101200100201201002
422033231203330311
5140012230121323
65015342013045
7536421062141
oct121755437465
931350321632
1011001020213
114735875347
122170277185
1310641c3b21
14765098221
15445be1828
hex28fb63f35

11001020213 has 4 divisors (see below), whose sum is σ = 11017127808. Its totient is φ = 10984912620.

The previous prime is 11001020203. The next prime is 11001020243. The reversal of 11001020213 is 31202010011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001020213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001020194 and 11001020203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001020203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8052773 + ... + 8054138.

It is an arithmetic number, because the mean of its divisors is an integer number (2754281952).

Almost surely, 211001020213 is an apocalyptic number.

It is an amenable number.

11001020213 is a deficient number, since it is larger than the sum of its proper divisors (16107595).

11001020213 is an equidigital number, since it uses as much as digits as its factorization.

11001020213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16107594.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11001020213 its reverse (31202010011), we get a palindrome (42203030224).

The spelling of 11001020213 in words is "eleven billion, one million, twenty thousand, two hundred thirteen".

Divisors: 1 683 16106911 11001020213