Base | Representation |
---|---|
bin | 1010000000010110000000… |
… | …0100011001100100111101 |
3 | 1102221200120012122000202122 |
4 | 2200011200010121210331 |
5 | 2420220043342324013 |
6 | 35221444502132325 |
7 | 2213540414504141 |
oct | 240054004314475 |
9 | 42850505560678 |
10 | 11001023011133 |
11 | 356156476a361 |
12 | 12980a44210a5 |
13 | 61a51335a09c |
14 | 2a0649393221 |
15 | 1412663d3a08 |
hex | a016011993d |
11001023011133 has 4 divisors (see below), whose sum is σ = 11003879681568. Its totient is φ = 10998166340700.
The previous prime is 11001023011129. The next prime is 11001023011151. The reversal of 11001023011133 is 33111032010011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11001023011133 - 22 = 11001023011129 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001023011633) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1428329441 + ... + 1428337142.
It is an arithmetic number, because the mean of its divisors is an integer number (2750969920392).
Almost surely, 211001023011133 is an apocalyptic number.
It is an amenable number.
11001023011133 is a deficient number, since it is larger than the sum of its proper divisors (2856670435).
11001023011133 is an equidigital number, since it uses as much as digits as its factorization.
11001023011133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2856670434.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11001023011133 its reverse (33111032010011), we get a palindrome (44112055021144).
The spelling of 11001023011133 in words is "eleven trillion, one billion, twenty-three million, eleven thousand, one hundred thirty-three".
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