1100110000049 has 2 divisors, whose sum is σ = 1100110000050. Its totient is φ = 1100110000048.

The previous prime is 1100110000043. The next prime is 1100110000051. The reversal of 1100110000049 is 9400000110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 815228410000 + 284881590049 = 902900^2 + 533743^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100110000049 is a prime.

Together with 1100110000051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100109999991 and 1100110000036.

It is not a weakly prime, because it can be changed into another prime (1100110000043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055000024 + 550055000025.

It is an arithmetic number, because the mean of its divisors is an integer number (550055000025).

Almost surely, 2^{1100110000049} is an apocalyptic number.

It is an amenable number.

1100110000049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100110000049 is an equidigital number, since it uses as much as digits as its factorization.

1100110000049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

The spelling of 1100110000049 in words is "one trillion, one hundred billion, one hundred ten million, forty-nine", and thus it is an aban number.