110011001001131 has 2 divisors, whose sum is σ = 110011001001132. Its totient is φ = 110011001001130.

The previous prime is 110011001001101. The next prime is 110011001001133. The reversal of 110011001001131 is 131100100110011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110011001001131 - 2³⁴ = 109993821131947 is a prime.

It is a super-2 number, since 2×110011001001131² (a number of 29 digits) contains 22 as substring.

Together with 110011001001133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110011001001133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500500565 + 55005500500566.

It is an arithmetic number, because the mean of its divisors is an integer number (55005500500566).

Almost surely, 2^{110011001001131} is an apocalyptic number.

110011001001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011001001131 is an equidigital number, since it uses as much as digits as its factorization.

110011001001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 110011001001131 its reverse (131100100110011), we get a palindrome (241111101111142).

The spelling of 110011001001131 in words is "one hundred ten trillion, eleven billion, one million, one thousand, one hundred thirty-one".