Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …010101001011011000101 |
3 | 10220011120120001212011011 |
4 | 100000203222221123011 |
5 | 121011011130310203 |
6 | 2201214503242221 |
7 | 142323515540365 |
oct | 20004352513305 |
9 | 3804516055134 |
10 | 1100110010053 |
11 | 39461046a19a |
12 | 159260749371 |
13 | 7c980815092 |
14 | 3b361d429a5 |
15 | 1d93a48176d |
hex | 10023aa96c5 |
1100110010053 has 2 divisors, whose sum is σ = 1100110010054. Its totient is φ = 1100110010052.
The previous prime is 1100110010029. The next prime is 1100110010123. The reversal of 1100110010053 is 3500100110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1092010370049 + 8099640004 = 1044993^2 + 89998^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100110010053 - 29 = 1100110009541 is a prime.
It is a super-2 number, since 2×11001100100532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100110010653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055005026 + 550055005027.
It is an arithmetic number, because the mean of its divisors is an integer number (550055005027).
Almost surely, 21100110010053 is an apocalyptic number.
It is an amenable number.
1100110010053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100110010053 is an equidigital number, since it uses as much as digits as its factorization.
1100110010053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 13.
Adding to 1100110010053 its reverse (3500100110011), we get a palindrome (4600210120064).
The spelling of 1100110010053 in words is "one trillion, one hundred billion, one hundred ten million, ten thousand, fifty-three".
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