Base | Representation |
---|---|
bin | 1010000000010110010010… |
… | …1110101010101101010011 |
3 | 1102221200202122202110000102 |
4 | 2200011210232222231103 |
5 | 2420220223401401321 |
6 | 35221500334043015 |
7 | 2213542354215503 |
oct | 240054456525523 |
9 | 42850678673012 |
10 | 11001101200211 |
11 | 35615a4913a31 |
12 | 129810664946b |
13 | 61a526605105 |
14 | 2a0655907a03 |
15 | 14126d1cac0b |
hex | a0164baab53 |
11001101200211 has 2 divisors, whose sum is σ = 11001101200212. Its totient is φ = 11001101200210.
The previous prime is 11001101200127. The next prime is 11001101200249. The reversal of 11001101200211 is 11200210110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001101200211 - 218 = 11001100938067 is a prime.
It is a super-3 number, since 3×110011012002113 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11001101200192 and 11001101200201.
It is not a weakly prime, because it can be changed into another prime (11001101260211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550600105 + 5500550600106.
It is an arithmetic number, because the mean of its divisors is an integer number (5500550600106).
Almost surely, 211001101200211 is an apocalyptic number.
11001101200211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001101200211 is an equidigital number, since it uses as much as digits as its factorization.
11001101200211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 11001101200211 its reverse (11200210110011), we get a palindrome (22201311310222).
The spelling of 11001101200211 in words is "eleven trillion, one billion, one hundred one million, two hundred thousand, two hundred eleven".
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