110011101109993 has 2 divisors, whose sum is σ = 110011101109994. Its totient is φ = 110011101109992.

The previous prime is 110011101109991. The next prime is 110011101110011. The reversal of 110011101109993 is 399901101110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61352552187369 + 48658548922624 = 7832787^2 + 6975568^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011101109993 - 2¹ = 110011101109991 is a prime.

Together with 110011101109991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (110011101109991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005550554996 + 55005550554997.

It is an arithmetic number, because the mean of its divisors is an integer number (55005550554997).

Almost surely, 2^{110011101109993} is an apocalyptic number.

It is an amenable number.

110011101109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011101109993 is an equidigital number, since it uses as much as digits as its factorization.

110011101109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187, while the sum is 37.

The spelling of 110011101109993 in words is "one hundred ten trillion, eleven billion, one hundred one million, one hundred nine thousand, nine hundred ninety-three".