110011101109991 has 2 divisors, whose sum is σ = 110011101109992. Its totient is φ = 110011101109990.

The previous prime is 110011101109909. The next prime is 110011101109993. The reversal of 110011101109991 is 199901101110011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110011101109991 - 2¹⁸ = 110011100847847 is a prime.

It is a super-4 number, since 4×110011101109991⁴ (a number of 57 digits) contains 4444 as substring.

Together with 110011101109993, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011101109993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005550554995 + 55005550554996.

It is an arithmetic number, because the mean of its divisors is an integer number (55005550554996).

Almost surely, 2^{110011101109991} is an apocalyptic number.

110011101109991 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011101109991 is an equidigital number, since it uses as much as digits as its factorization.

110011101109991 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 729, while the sum is 35.

The spelling of 110011101109991 in words is "one hundred ten trillion, eleven billion, one hundred one million, one hundred nine thousand, nine hundred ninety-one".