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11001111000043 is a prime number
BaseRepresentation
bin1010000000010110010101…
…0100000011001111101011
31102221200210100012022212011
42200011211110003033223
52420220233404000133
635221501324100351
72213542533422443
oct240054524031753
942850710168764
1011001111000043
1135615aa3a776a
1212981099946b7
1361a528656828
142a0656d39123
1514126deb46cd
hexa01655033eb

11001111000043 has 2 divisors, whose sum is σ = 11001111000044. Its totient is φ = 11001111000042.

The previous prime is 11001111000023. The next prime is 11001111000079. The reversal of 11001111000043 is 34000011110011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001111000043 - 237 = 10863672046571 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001110999987 and 11001111000032.

It is not a weakly prime, because it can be changed into another prime (11001111000023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555500021 + 5500555500022.

It is an arithmetic number, because the mean of its divisors is an integer number (5500555500022).

Almost surely, 211001111000043 is an apocalyptic number.

11001111000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001111000043 is an equidigital number, since it uses as much as digits as its factorization.

11001111000043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11001111000043 its reverse (34000011110011), we get a palindrome (45001122110054).

The spelling of 11001111000043 in words is "eleven trillion, one billion, one hundred eleven million, forty-three", and thus it is an aban number.