Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …110110011100001100111 |
3 | 10220011120122010020021211 |
4 | 100000203232303201213 |
5 | 121011011420200012 |
6 | 2201214542452251 |
7 | 142323531030163 |
oct | 20004356634147 |
9 | 3804518106254 |
10 | 1100111100007 |
11 | 394611044087 |
12 | 159260b94087 |
13 | 7c980b0721a |
14 | 3b362147ca3 |
15 | 1d93a5e96a7 |
hex | 10023bb3867 |
1100111100007 has 2 divisors, whose sum is σ = 1100111100008. Its totient is φ = 1100111100006.
The previous prime is 1100111099987. The next prime is 1100111100031. The reversal of 1100111100007 is 7000011110011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100111100007 is a prime.
It is a super-2 number, since 2×11001111000072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1100111100007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100111106007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055550003 + 550055550004.
It is an arithmetic number, because the mean of its divisors is an integer number (550055550004).
Almost surely, 21100111100007 is an apocalyptic number.
1100111100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111100007 is an equidigital number, since it uses as much as digits as its factorization.
1100111100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 13.
Adding to 1100111100007 its reverse (7000011110011), we get a palindrome (8100122210018).
The spelling of 1100111100007 in words is "one trillion, one hundred billion, one hundred eleven million, one hundred thousand, seven".
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