11001114341300 has 18 divisors (see below), whose sum is σ = 23872418120838. Its totient is φ = 4400445736480.

The previous prime is 11001114341299. The next prime is 11001114341317. The reversal of 11001114341300 is 314341110011.

It can be written as a sum of positive squares in 3 ways, for example, as 3007907486224 + 7993206855076 = 1734332^2 + 2827226^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55005571607 + ... + 55005571806.

Almost surely, 2^{11001114341300} is an apocalyptic number.

11001114341300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11001114341300 is an abundant number, since it is smaller than the sum of its proper divisors (12871303779538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001114341300 is a wasteful number, since it uses less digits than its factorization.

11001114341300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110011143427 (or 110011143420 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11001114341300 its reverse (314341110011), we get a palindrome (11315455451311).

The spelling of 11001114341300 in words is "eleven trillion, one billion, one hundred fourteen million, three hundred forty-one thousand, three hundred".