11001120253 has 2 divisors, whose sum is σ = 11001120254. Its totient is φ = 11001120252.

The previous prime is 11001120241. The next prime is 11001120307. The reversal of 11001120253 is 35202110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5603720164 + 5397400089 = 74858^2 + 73467^2 .

It is an emirp because it is prime and its reverse (35202110011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001120253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001120203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500560126 + 5500560127.

It is an arithmetic number, because the mean of its divisors is an integer number (5500560127).

Almost surely, 2^11001120253 is an apocalyptic number.

It is an amenable number.

11001120253 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001120253 is an equidigital number, since it uses as much as digits as its factorization.

11001120253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 11001120253 its reverse (35202110011), we get a palindrome (46203230264).

The spelling of 11001120253 in words is "eleven billion, one million, one hundred twenty thousand, two hundred fifty-three".