1100112621403 has 2 divisors, whose sum is σ = 1100112621404. Its totient is φ = 1100112621402.

The previous prime is 1100112621401. The next prime is 1100112621463. The reversal of 1100112621403 is 3041262110011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100112621403 - 2¹ = 1100112621401 is a prime.

Together with 1100112621401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100112621401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056310701 + 550056310702.

It is an arithmetic number, because the mean of its divisors is an integer number (550056310702).

Almost surely, 2^{1100112621403} is an apocalyptic number.

1100112621403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100112621403 is an equidigital number, since it uses as much as digits as its factorization.

1100112621403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1100112621403 its reverse (3041262110011), we get a palindrome (4141374731414).

The spelling of 1100112621403 in words is "one trillion, one hundred billion, one hundred twelve million, six hundred twenty-one thousand, four hundred three".