11001132303191 has 2 divisors, whose sum is σ = 11001132303192. Its totient is φ = 11001132303190.

The previous prime is 11001132303173. The next prime is 11001132303193. The reversal of 11001132303191 is 19130323110011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001132303191 is a prime.

It is a super-4 number, since 4×11001132303191⁴ (a number of 53 digits) contains 4444 as substring.

Together with 11001132303193, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11001132303191.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001132303193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500566151595 + 5500566151596.

It is an arithmetic number, because the mean of its divisors is an integer number (5500566151596).

Almost surely, 2^{11001132303191} is an apocalyptic number.

11001132303191 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001132303191 is an equidigital number, since it uses as much as digits as its factorization.

11001132303191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 26.

The spelling of 11001132303191 in words is "eleven trillion, one billion, one hundred thirty-two million, three hundred three thousand, one hundred ninety-one".