11001203220113 has 4 divisors (see below), whose sum is σ = 11001262193520. Its totient is φ = 11001144246708.

The previous prime is 11001203220107. The next prime is 11001203220169. The reversal of 11001203220113 is 31102230210011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001203220113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001203220091 and 11001203220100.

It is not an unprimeable number, because it can be changed into a prime (11001203220173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29205995 + ... + 29580272.

It is an arithmetic number, because the mean of its divisors is an integer number (2750315548380).

Almost surely, 2^{11001203220113} is an apocalyptic number.

It is an amenable number.

11001203220113 is a deficient number, since it is larger than the sum of its proper divisors (58973407).

11001203220113 is an equidigital number, since it uses as much as digits as its factorization.

11001203220113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58973406.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11001203220113 its reverse (31102230210011), we get a palindrome (42103433430124).

The spelling of 11001203220113 in words is "eleven trillion, one billion, two hundred three million, two hundred twenty thousand, one hundred thirteen".