Base | Representation |
---|---|
bin | 11001000000111000110001… |
… | …011001100011001011001010 |
3 | 112102112001111212112111210211 |
4 | 121000320301121203023022 |
5 | 103404414311000213002 |
6 | 1025550512025031334 |
7 | 32113053626261461 |
oct | 3100706131431312 |
9 | 472461455474724 |
10 | 110012121101002 |
11 | 3206497339583a |
12 | 1040910492554a |
13 | 4950138557083 |
14 | 1d24887a839d8 |
15 | caba03904dd7 |
hex | 640e316632ca |
110012121101002 has 8 divisors (see below), whose sum is σ = 165018381480000. Its totient is φ = 55005993941004.
The previous prime is 110012121100993. The next prime is 110012121101053. The reversal of 110012121101002 is 200101121210011.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1100121211010023 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31214002 + ... + 34559197.
It is an arithmetic number, because the mean of its divisors is an integer number (20627297685000).
Almost surely, 2110012121101002 is an apocalyptic number.
110012121101002 is a deficient number, since it is larger than the sum of its proper divisors (55006260378998).
110012121101002 is an equidigital number, since it uses as much as digits as its factorization.
110012121101002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66609500.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 110012121101002 its reverse (200101121210011), we get a palindrome (310113242311013).
The spelling of 110012121101002 in words is "one hundred ten trillion, twelve billion, one hundred twenty-one million, one hundred one thousand, two".
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