110012213293 has 2 divisors, whose sum is σ = 110012213294. Its totient is φ = 110012213292.

The previous prime is 110012213239. The next prime is 110012213309. The reversal of 110012213293 is 392312210011.

Together with previous prime (110012213239) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65475597924 + 44536615369 = 255882^2 + 211037^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012213293 - 2¹⁷ = 110012082221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110012213593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006106646 + 55006106647.

It is an arithmetic number, because the mean of its divisors is an integer number (55006106647).

Almost surely, 2^110012213293 is an apocalyptic number.

It is an amenable number.

110012213293 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012213293 is an equidigital number, since it uses as much as digits as its factorization.

110012213293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 110012213293 in words is "one hundred ten billion, twelve million, two hundred thirteen thousand, two hundred ninety-three".