Base | Representation |
---|---|
bin | 110011001110100111… |
… | …1010010100000111101 |
3 | 101111221221101110212212 |
4 | 1212131033102200331 |
5 | 3300301111311214 |
6 | 122312223310205 |
7 | 10643130245525 |
oct | 1463517224075 |
9 | 344857343785 |
10 | 110012213309 |
11 | 42724032159 |
12 | 193a2a4b365 |
13 | a4b2bb500b |
14 | 5478a82685 |
15 | 2cdd20b53e |
hex | 199d3d283d |
110012213309 has 2 divisors, whose sum is σ = 110012213310. Its totient is φ = 110012213308.
The previous prime is 110012213293. The next prime is 110012213401. The reversal of 110012213309 is 903312210011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102909432025 + 7102781284 = 320795^2 + 84278^2 .
It is an emirp because it is prime and its reverse (903312210011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110012213309 - 24 = 110012213293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110012213609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006106654 + 55006106655.
It is an arithmetic number, because the mean of its divisors is an integer number (55006106655).
Almost surely, 2110012213309 is an apocalyptic number.
It is an amenable number.
110012213309 is a deficient number, since it is larger than the sum of its proper divisors (1).
110012213309 is an equidigital number, since it uses as much as digits as its factorization.
110012213309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 110012213309 in words is "one hundred ten billion, twelve million, two hundred thirteen thousand, three hundred nine".
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