1100124521437 has 2 divisors, whose sum is σ = 1100124521438. Its totient is φ = 1100124521436.

The previous prime is 1100124521371. The next prime is 1100124521453. The reversal of 1100124521437 is 7341254210011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1033772428516 + 66352092921 = 1016746^2 + 257589^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100124521437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100124521399 and 1100124521408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100124221437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550062260718 + 550062260719.

It is an arithmetic number, because the mean of its divisors is an integer number (550062260719).

Almost surely, 2^{1100124521437} is an apocalyptic number.

It is an amenable number.

1100124521437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100124521437 is an equidigital number, since it uses as much as digits as its factorization.

1100124521437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 1100124521437 its reverse (7341254210011), we get a palindrome (8441378731448).

The spelling of 1100124521437 in words is "one trillion, one hundred billion, one hundred twenty-four million, five hundred twenty-one thousand, four hundred thirty-seven".