11001300953 has 2 divisors, whose sum is σ = 11001300954. Its totient is φ = 11001300952.

The previous prime is 11001300917. The next prime is 11001301021. The reversal of 11001300953 is 35900310011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7254269584 + 3747031369 = 85172^2 + 61213^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001300953 - 2⁸ = 11001300697 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001300853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500650476 + 5500650477.

It is an arithmetic number, because the mean of its divisors is an integer number (5500650477).

Almost surely, 2^11001300953 is an apocalyptic number.

It is an amenable number.

11001300953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001300953 is an equidigital number, since it uses as much as digits as its factorization.

11001300953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405, while the sum is 23.

Adding to 11001300953 its reverse (35900310011), we get a palindrome (46901610964).

The spelling of 11001300953 in words is "eleven billion, one million, three hundred thousand, nine hundred fifty-three".