110013101320013 has 2 divisors, whose sum is σ = 110013101320014. Its totient is φ = 110013101320012.

The previous prime is 110013101319899. The next prime is 110013101320103. The reversal of 110013101320013 is 310023101310011.

Together with next prime (110013101320103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98426994997444 + 11586106322569 = 9921038^2 + 3403837^2 .

It is a cyclic number.

It is not a de Polignac number, because 110013101320013 - 2¹⁴ = 110013101303629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110013101319973 and 110013101320000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013101325013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006550660006 + 55006550660007.

It is an arithmetic number, because the mean of its divisors is an integer number (55006550660007).

Almost surely, 2^{110013101320013} is an apocalyptic number.

It is an amenable number.

110013101320013 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013101320013 is an equidigital number, since it uses as much as digits as its factorization.

110013101320013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 110013101320013 its reverse (310023101310011), we get a palindrome (420036202630024).

The spelling of 110013101320013 in words is "one hundred ten trillion, thirteen billion, one hundred one million, three hundred twenty thousand, thirteen".